Model Selection Series HRZ Required Cooling Capacity Calculation Example 1: When the heat generation amount in the customer’s machine is known. Cooling capacity = Considering a safety factor of 20%, 3.5 x 1.2 = 4.2 kW Heat generation amount Q: 3.5 kW Example 2: When the heat generation amount in the customer’s machine is not known. : Unknown : 6.0°C (6.0 K) : 20°C (293.15 K) : 26°C (299.15 K) : 20 L/min : Fluorinated fluid Density �､: 1.80 x 103 kg/m3 Specific heat C: 0.96 x 103 J/(kg・K) (at 20°C) Obtain the temperature difference between inlet and outlet by circulating the circulating fluid inside the customer’s machine. Heat generation amount Q Circulating fluid temperature difference �ｪT (= T2 . T1) Circulating fluid outlet temperature T1 Circulating fluid return temperature T2 Circulating fluid flow rate L Circulating fluid . Refer to page 1323 for the typical physical property values by circulating fluid. Q = �ｪT x L x �､ x C 60 x 1000 6.0 x 20 x 1.80 x 103 x 0.96 x 103 60 x 1000 = 3456 W = 3.5 kW = Cooling capacity = Considering a safety factor of 20%, 3.5 x 1.2 = 4.2 kW L Thermo-chiller T2: Return temperature �ｪT = T2 . T1 T1: Outlet temperature Customer’s machine Unknown 6.0°C 20°C 26°C 1.2 m3/h Fluorinated fluid Density �､: 1.80 x 103 kg/m3 Specific heat°C: 0.23 kcal/kg・°C (at 20°C) . Refer to page 1323 for the typical physical property values by circulating fluid. Example of conventional measurement units (Reference) Cooling capacity = Considering a safety factor of 20%, 3.5 x 1.2 = 4.2 kW Q = �ｪT x L x �､ x C 860 6.0 x 1.2 x 1.80 x 103 x 0.23 860 = 3.5 kW = 1321 HRG HRS HRZD HRW HEC HEB HED HEA IDH HRZ