119 L1 Mep m T1 a1 a2 L Speed: V [mm/s] Time [s] T2 T3 T4 100 W Speed: V [mm/s] Work load: W [kg] 0 1000 1500 2000 0 10 20 30 40 LEFB40 LEFB25 LEFB32 0 500 1000 0 10 20 30 40 50 60 Work load [kg] Overhang: L1 [mm] 100 1000 mm/s2 3000 mm/s2 5000 mm/s2 10000 mm/s2 20000 mm/s2 Selection Procedure Selection Example Step 1 Check the work load.speed. Step 2 Check the cycle time. Step 3 Check the allowable moment. Workpiece mass: 20 [kg] Speed: 1500 [mm/s] Acceleration/Deceleration: 3000 [mm/s2] Stroke: 2000 [mm] Mounting position: Horizontal upward Workpiece mounting condition: Operating conditions (LEFB40) Step 1 Check the work load.speed. (Page 120) Select the target model based on the workpiece mass and speed with reference to the . Selection example) The LEFB40S4S-2000 is temporarily selected based on the graph shown on the right side. Step 2 Check the cycle time. Calculate the cycle time using the following calculation method. Cycle time: T can be found from the following equation. T = T1 + T2 + T3 + T4 [s] T4 = 0.05 [s] T1 = V/a1 [s] T3 = V/a2 [s] T2 = [s] L . 0.5 ・ V ・ (T1 + T3) V T4: Settling time varies depending on the conditions such as motor types, load and in positioning of the step data. Therefore, calculate the settling time with reference to the following value. T1: Acceleration time and T3: Deceleration time can be obtained by the following equation. Step 3 Check the guide moment. Based on the above calculation result, the LEFB40S4S-2000 is selected. L : Stroke [mm] ・・・ (Operating condition) V : Speed [mm/s] ・・・ (Operating condition) a1: Acceleration [mm/s2] ・・・ (Operating condition) a2: Deceleration [mm/s2] ・・・ (Operating condition) T1: Acceleration time [s] Time until reaching the set speed T2: Constant speed time [s] Time while the actuator is operating at a constant speed T3: Deceleration time [s] Time from the beginning of the constant speed operation to stop T4: Settling time [s] Time until in position is completed Calculation example) T1 to T4 can be calculated as follows. T1 = V/a1 = 1500/3000 = 0.5 [s], T3 = V/a2 = 1500/3000 = 0.5 [s] T4 = 0.05 [s] Therefore, the cycle time can be obtained as follows. T = T1 + T2 + T3 + T4 = 0.5 + 0.83 + 0.5 + 0.05 = 1.88 [s] T2 = = = 0.83 [s] L . 0.5 ・ V ・ (T1 + T3) V 2000 . 0.5 ・ 1500 ・ (0.5 + 0.5) 1500 Electric Actuator/Slider Type Belt Drive/Series LEFB Model Selection T2: Constant speed time can be found from the following equation. AC Servo Motor
